7/(x^2+8x+23)=1

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Solution for 7/(x^2+8x+23)=1 equation: 


D( x )

x^2+8*x+23 = 0

x^2+8*x+23 = 0

x^2+8*x+23 = 0

x^2+8*x+23 = 0

DELTA = 8^2-(1*4*23)

DELTA = -28

DELTA < 0

x in (-oo:+oo)

7/(x^2+8*x+23) = 1 // - 1

7/(x^2+8*x+23)-1 = 0

x^2+8*x+23 = 0

x^2+8*x+23 = 0

x^2+8*x+23 = 0

DELTA = 8^2-(1*4*23)

DELTA = -28

DELTA < 0

1 = 0

7-1 = 0

7-1 = 0

6 = 0

6 = 0

x belongs to the empty set

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